运气测试
#include <bits/stdc++.h>
using namespace std;
int st = clock();
int main() {
int a, b; scanf("%d%d", &a, &b);
printf("%d", a + b);
while (clock() - st < 999960) {}
return 0;
}
用这个代码提交 A+B Problem,然后看 AC 了几个点
| AC 个数 | 运气成分(%) |
|---|---|
| 0 | 10% |
| 1 | 30% |
| 2 | 60% |
| 3 | 80% |
| 4 | 90% |
| 5 | 98% |
| 6 | 99% |
| 7 | 99.8% |
| 8 | 99.98% |
| 9 | 99.999999999% |
| 10 | 100% |