乘法逆元
陈子骏
2018-04-02 17:44:24
```
#include<cstdio>
using namespace std;
int n,m;
int exgcd(int a,int b,int &x,int &y)
{
if(b==0)
{
x=1;
y=0;
return a;
}
int r=exgcd(b,a%b,x,y),t=x;
x=y;
y=t-(a/b)*y;
return r;
}
int main()
{
int x,y;
scanf("%d%d",&n,&m);
for(int i=1;i<=n;i++)
{
exgcd(i,m,x,y);
printf("%d\n",(x+m)%m);
}
return 0;
}
```