草算纸
interestingLSY
2018-07-14 12:26:46
$$f_i = min\{f_j+Tran_{i,j}+Cost_i\}\qquad j \in [1,i-1]$$
.
$$Tran_{i,j} = \Sigma_{k=j+1}^{i-1}(dis_i-dis_k)*num_k$$
$$=dis_i*\Sigma_{k=j+1}^{i-1}num_k\ -\ \Sigma_{k=j+1}^{i-1}dis_k*num_k $$
.
$$sum_x = \Sigma_{i=1}^{x}num_i$$
$$g_x = \Sigma_{i=1}^{x}dis_i*num_i$$
$$\therefore Tran_{i,j} = dis_i*(sum_{i-1}-sum_{j})\ -\ (g_{i-1}-g_j)$$
.
$$\therefore f_i = min\{f_j+Tran_{i,j}+Cost_i\}\qquad j \in [1,i-1]$$
$$f_i = min\{f_j+dis_i*(sum_{i-1}-sum_{j})\ -\ (g_{i-1}-g_j)+Cost_i\}\qquad j \in [1,i-1]$$
$$= min\{f_j+dis_i*sum_{i-1}-dis_i*sum_{j}\ -\ g_{i-1}+g_j+Cost_i\}\qquad j \in [1,i-1]$$
$$= f_j-dis_i*sum_{j}+g_j+dis_i*sum_{i-1}-g_{i-1}+Cost_i\qquad j \in [1,i-1]$$
$$f_i+dis_i*sum_j = f_j+g_j$$
$$b\ \ \ \ +\ \ \ k\ \ *\ \ x \ \ \ =\ \ \ \ \ y$$