题解 AT1995 【Range Product】

LJC00111 · 2018-03-30 16:55:06 · 题解

#include<bits/stdc++.h>
using namespace std;
long long n,m;
int main()
{
    cin>>n>>m;
    if(n==0||m==0)
    cout<<"Zero"<<endl;
    if(n>0&&m>0)
    cout<<"Positive"<<endl;
    else if(n>0&&m<0)cout<<"Zero"<<endl;
    else if(n<0&&m>0)cout<<"Zero"<<endl;
    else if(n<0&&m<0)
    {
        if((n-m)%2==0)
        cout<<"Negative"<<endl;
        else cout<<"Positive"<<endl;
    }
    return 0;
}