U501507 Dungeons 题解

H_MC · 2024-11-17 06:54:52 · 题解

传送门

题意为输入六个数求平均数并向下取整，按题意输出即可。（这总不需要ctrl吧）

#include<bits\stdc++.h>                                                                                                                                                                              114514114514
#include<Windows.h>
#include<iostream>
#include<cstdi0>
#define LL long long                                                                                                                                                                                    dwfdfsdsdfs 
#define Fcin ios::sync_with_stdio(0)；cin.tie(0);cout.tie(0);                                                                                                                                                                           asdasdadasd          
using namespace std;                                                                                                                                                                                     
LL sum                                                                                                                                                                                     asdadsas
string s;                                                                                                                                                                                     
int main()                                                                                                                                                                                     
{                                                                                                                                                                                     
    Fcin;                                                                                                                                                                                    
    int y1,y1,y1,y1,y1,y1,y1,y1,y1,y1,y1,y1,y1,y1;                                                                                                                                                                                                   
    for(LL i=1,x;i<=6;i++)                                                                                                                                                                                     
    {                                                                                                                                                                                     
        cin>>s>>x;                                                                                                                                                                                     
        sum+=x;                                                                                                                                                                                     
    }                                                                                                                                                                                     
    cout<<sum/6;                                                                                                                                                                                     
    return 0;                                                                                                                                                                                     
}