题解 P5055 【【模板】可持久化文艺平衡树】
啥时候“文艺平衡树”成了 Splay 的代称了……
果断写了个 FHQ Treap,然后 30pts。
求助大佬之后发现标记下传时也要新建结点。
以及合并的时候不必新建结点,因为分裂时已经新建了,否则会 MLE。
代码:
#include <cstdio>
#include <algorithm>
#include <cstdlib>
#define ls(p) tree[p].lson
#define rs(p) tree[p].rson
using namespace std;
const int N = 2e5;
int n;
long long lastans;
struct node
{
int rnd,sz,rev;
long long val,sum;
int lson,rson;
} tree[(N << 7) + 10];
int rt[N + 10];
inline int new_node(long long v = 0)
{
static int tot = 0;
tree[++tot].val = v;
tree[tot].sum = v;
tree[tot].rnd = rand();
tree[tot].sz = 1;
return tot;
}
inline int copy_node(int p)
{
int ret = new_node();
tree[ret] = tree[p];
return ret;
}
inline void up(int p)
{
tree[p].sz = tree[ls(p)].sz + 1 + tree[rs(p)].sz;
tree[p].sum = tree[ls(p)].sum + tree[p].val + tree[rs(p)].sum;
}
inline void down(int p)
{
if(tree[p].rev)
{
if(ls(p))
ls(p) = copy_node(ls(p));
if(rs(p))
rs(p) = copy_node(rs(p));
swap(ls(p),rs(p));
if(ls(p))
tree[ls(p)].rev ^= 1;
if(rs(p))
tree[rs(p)].rev ^= 1;
tree[p].rev = 0;
}
}
void split(int p,int k,int &x,int &y)
{
if(!p)
{
x = y = 0;
return ;
}
down(p);
if(tree[ls(p)].sz < k)
x = copy_node(p),split(rs(x),k - tree[ls(p)].sz - 1,rs(x),y),up(x);
else
y = copy_node(p),split(ls(y),k,x,ls(y)),up(y);
}
int merge(int x,int y)
{
if(!x || !y)
return x | y;
down(x),down(y);
if(tree[x].rnd < tree[y].rnd)
{
rs(x) = merge(rs(x),y);
up(x);
return x;
}
else
{
ls(y) = merge(x,ls(y));
up(y);
return y;
}
}
int main()
{
srand(19260817);
scanf("%d",&n);
int cnt = 0;
int v,op;
long long a,b;
int x,y,z;
while(n--)
{
scanf("%d%d",&v,&op);
if(op == 1)
{
scanf("%lld%lld",&a,&b);
a ^= lastans,b ^= lastans;
split(rt[v],a,x,y);
rt[++cnt] = merge(merge(x,new_node(b)),y);
}
else if(op == 2)
{
scanf("%lld",&a);
a ^= lastans;
split(rt[v],a,x,z);
split(x,a - 1,x,y);
rt[++cnt] = merge(x,z);
}
else if(op == 3)
{
scanf("%lld%lld",&a,&b);
a ^= lastans,b ^= lastans;
split(rt[v],b,x,z);
split(x,a - 1,x,y);
tree[y].rev ^= 1;
rt[++cnt] = merge(merge(x,y),z);
}
else
{
scanf("%lld%lld",&a,&b);
a ^= lastans,b ^= lastans;
split(rt[v],b,x,z);
split(x,a - 1,x,y);
printf("%lld\n",lastans = tree[y].sum);
rt[++cnt] = merge(merge(x,y),z);
}
}
}