~~拼音做变量名的神人%%%~~
没看题，代码扫了一眼，估计dfs死循环
by 无意识躺枪人 @ 2019-02-16 19:22:46
这不是斐波那契吗QwQ
by t162 @ 2019-02-16 19:23:34
@[scp_05_tqr](/space/show?uid=117842) 啊？我有return啊。。。
by Konjacer @ 2019-02-16 19:23:36
变化的斐波那契呀QwQ
by t162 @ 2019-02-16 19:23:55
就算你的算法是对的，也会超时
by YZhe @ 2019-02-16 19:24:32
什么时候teijie会是0啊QwQ
by t162 @ 2019-02-16 19:25:07
@[Imitater](/space/show?uid=151696)
dfs的ruturn？
by 灵光一闪 @ 2019-02-16 19:25:18
```cpp
void dfs(long long taijie,long long step)
{
if(taijie==0)
{
ans++;
/*cout<<"judge";*/
return;
}
else
for(int i=1;i<=step;++i)
{
if(taijie-i>=0)
dfs(taijie-i,step);
}
}
```
by t162 @ 2019-02-16 19:26:13
@[Bambusoideae](/space/show?uid=106140) 嘶~妙啊。。
by Konjacer @ 2019-02-16 19:26:19
@[Imitater](/space/show?uid=151696) 递归里的return...
by wwlw @ 2019-02-16 19:26:52