月赛t2

站务版

没看懂 很无奈啊
by dengwenjun @ 2019-03-02 14:57:21


$C_n^m, m \le n$
by kkksc03 @ 2019-03-02 14:58:10


kkk ! (其实m > n的情况C(n,m)=0)
by Le_temps_des_fleurs @ 2019-03-02 14:58:36


数据范围有么……(思路考虑是爆算还是~~弃疗~~其他)
by Victory_Defeat @ 2019-03-02 15:13:12


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