嘤我怎么自带大常数啊QAQ

P5268 [SNOI2017] 一个简单的询问

~~嘤开头像妹子~~ %%%
by 樱初音斗橡皮 @ 2019-03-23 21:23:02


我这里有个大整数程序,可以参考一下: ```cpp #include <cstdio> #include <cstring> #include <algorithm> #include <iostream> using namespace std; #define maxn 10000 #define base 10000 struct Bign { int c[maxn],len,sign; //初始化 Bign(){memset(c,0,sizeof(c)),len = 1,sign = 0;} //清高位零 void Zero() { while(len > 1 && c[len] == 0)len--; if(len == 1 && c[len] == 0)sign = 0; } //压位读入 void Write(char *s) { int k = 1,l = strlen(s); for(int i = l - 1;i >= 0;i--) { c[len] += (s[i] - '0') * k; k *= 10; if(k == base) { k = 1; len++; } } } void Read() { char s[maxn] = {0}; scanf("%s",s); Write(s); } //输出 void Print() { if(sign)printf("-"); printf("%d",c[len]); for(int i = len - 1;i >= 1;i--)printf("%04d",c[i]); printf("\n"); } //重载 = 运算符,将低精赋值给高精 Bign operator = (int a) { char s[100]; sprintf(s,"%d",a); Write(s); return *this; } //重载 < 运算符 bool operator < (const Bign &a)const { if(len != a.len)return len < a.len; for(int i = len;i >= 1;i--) { if(c[i] != a.c[i])return c[i] < a.c[i]; } return 0; } bool operator > (const Bign &a)const { return a < *this; } bool operator <= (const Bign &a)const { return !(a < *this); } bool operator >= (const Bign &a)const { return !(*this < a); } bool operator != (const Bign &a)const { return a < *this || *this < a; } bool operator == (const Bign &a)const { return !(a < *this) && !(*this < a); } bool operator == (const int &a)const { Bign b;b = a; return *this == b; } //重载 + 运算符 Bign operator + (const Bign &a) { Bign r; r.len = max(len,a.len) + 1; for(int i = 1;i <= r.len;i++) { r.c[i] += c[i] + a.c[i]; r.c[i + 1] += r.c[i] / base; r.c[i] %= base; } r.Zero(); return r; } Bign operator + (const int &a) { Bign b;b = a; return *this + b; } //重载 - 运算符 Bign operator - (const Bign &a) { Bign b,c;// b - c b = *this; c = a; if(c > b) { Bign t; t = b;b = c;c = t; b.sign = 1; } for(int i = 1;i <= b.len;i++) { b.c[i] -= c.c[i]; if(b.c[i] < 0) { b.c[i] += base; b.c[i + 1]--; } } b.Zero(); return b; } Bign operator - (const int &a) { Bign b;b = a; return *this - b; } //重载 * 运算符 Bign operator * (const Bign &a) { Bign r; r.len = len + a.len + 2; for(int i = 1;i <= len;i++) { for(int j = 1;j <= a.len;j++) { r.c[i + j - 1] += c[i] * a.c[j]; } } for(int i = 1;i <= r.len;i++) { r.c[i + 1] += r.c[i] / base; r.c[i] %= base; } r.Zero(); return r; } Bign operator * (const int &a) { Bign b;b = a; return *this * b; } //重载 / 运算符 Bign operator / (const Bign &b) { Bign r,t,a; a = b; if(a == 0)return r; r.len =len; for(int i = len;i >= 1;i--) { t = t * base + c[i]; int div,ll = 0,rr = base; while(ll <= rr) { int mid = (ll + rr) / 2; Bign k = a * mid; if(k > t)rr = mid - 1; else { ll = mid + 1; div = mid; } } r.c[i] = div; t = t - a * div; } r.Zero(); return r; } Bign operator / (const int &a) { Bign b;b = a; return *this / b; } //重载 % 运算符 Bign operator % (const Bign &a) { return *this - *this / a * a; } Bign operator % (const int &a) { Bign b;b = a; return *this % b; } }; int main() { // freopen("Bign.in","r",stdin); // freopen("Bign.out","w",stdout); Bign a,b,c,d,e,f,g; a.Read(); b.Read(); c = a + b; c.Print(); d = a - b; d.Print(); e = a * b; e.Print(); f = a / b; f.Print(); g = a % b; g.Print(); return 0; } ```
by Eason_AC @ 2019-03-23 21:25:20


@[Eason_AC](/space/show?uid=112917) ???
by hsfzLZH1 @ 2019-03-23 21:26:11


@[Eason_AC](/space/show?uid=112917) ...乘法不用fft差评
by 樱初音斗橡皮 @ 2019-03-23 21:26:11


%%% 深蓝大佬
by _Life_ @ 2019-03-23 21:26:27


@[Eason_AC](/space/show?uid=112917) ~~大常数和大整数不是一个东西~~
by 樱初音斗橡皮 @ 2019-03-23 21:26:41


@[Eason_AC](/space/show?uid=112917) 蛤???
by _Life_ @ 2019-03-23 21:26:52


~~没有fft的乘法看都不要看~~
by 樱初音斗橡皮 @ 2019-03-23 21:26:58


@[Eason_AC](/space/show?uid=112917) first,我说的是大常数,而非大整数。 second,乘除法时间复杂度太大,有也不要
by NaCly_Fish @ 2019-03-23 21:28:14


嗯?可能我不是用的大常数,不好意思
by Eason_AC @ 2019-03-23 21:28:18


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