```cpp
#include<iostream>
using namespace std;
int a[10]={6,2,5,5,4,5,6,3,7,6};
int b[2005]={6};
int main(){
int n=0;
cin>>n;
int c=0;
for(int i=1;i<=2000;i++){
c=i;
while(c!=0){
b[i]+=a[c%10];
c=c/10;
}
}
int ans=0;
for(int i=0;i<=1000;i++){
for(int j=0;j<=1000;j++){
if(b[i]+b[j]+b[i+j]+4==n){
ans++;
}
}
}
cout<<ans<<endl;
return 0;
}
```
可以参考一下
by Revenge_LJX @ 2019-08-02 08:00:53
@[森森鸭](/space/show?uid=216176) 你这样只是做了个位的 万一A或B或C为十位数呢
by Revenge_LJX @ 2019-08-02 08:02:52
@[Revenge_LJX](/space/show?uid=230111) 好的谢谢啦！！！
by 森森鸭 @ 2019-08-02 15:46:28
#include<iostream>
#include<cstdio>
#include<cstring>
using namespace std;
int hcb[10]={6,2,5,5,4,5,6,3,7,6},nn;
inline void num(int i)
{
if(i==0)
nn+=6;
while(i!=0)
{
nn+=(i%10==0?hcb[0]:hcb[i%10]);
i/=10;
}
}
int main()
{
int n,ans=0;
scanf("%d",&n);
n-=4;
for(register int i=0;i<1111;i++)
for(register int j=0;j<1111;j++)
{
nn=0;
num(i);
num(j);
num(i+j);
if(nn==n)
{
ans++;
}
}
printf("%d",ans);
}
by 神通之乐 @ 2019-09-09 21:22:20