为什么不试试用字符数组 char[] 呢？
by Tsukimaru @ 2017-07-26 16:57:51
```cpp
#include<iostream>
using namespace std;
string pl,gr;
int i,s1=1,s2=1;
int main()
{
cin>>pl>>gr;
for (i=0;i<=pl.size();i++)
{
s1*=(pl[i]-'A'+1)%47;
s1=s1%47;
}
for (i=0;i<=gr.size();i++)
{
s2*=(gr[i]-'A'+1)%47;
s2=s2%47;
}
if (s1==s2) cout<<"GO";
else cout<<"STAY";
return 0;
}
///string做法如上
```
by DanStevens @ 2017-08-05 21:12:19