你们的代码就不能体现一下简洁性吗？
```cpp
#include<bits/stdc++.h>
using namespace std;
const int N=205;
int n,x,y,scorea,scoreb,a[N],b[N];
int p[5][5]={0,-1,1,1,-1,
```
1,0,-1,1,-1,
-1,1,0,-1,1,
-1,-1,1,0,1,
```cpp
1,1,-1,-1,0};
int main()
{
scanf("%d%d%d",&n,&x,&y);
for (int i=0;i<x;++i)
scanf("%d",&a[i]);
for (int i=0;i<y;++i)
scanf("%d",&b[i]);
for (int i=0;i<n;++i)
{
if (p[a[i%x]][b[i%y]]==1) ++scorea;
else if (p[a[i%x]][b[i%y]]==-1) ++scoreb;
}
printf("%d %d\n",scorea,scoreb);
return 0;
}
这样多好懂。
```
by zk2351265864 @ 2017-08-29 10:23:32
为什么平局要break呢
```cpp
#include<iostream>
#include<cstdlib>
#include<cstdio>
using namespace std;
int a[201],b[201];
int main()
{
int N,A,B,ai=0,bi=0,ap=0,bp=0;
cin>>N>>A>>B;
for(int i=1;i<=A;i++)
cin>>a[i];
for(int i=1;i<=B;i++)
cin>>b[i];
for(int i=1;i<=N;i++)
{
ai++;
bi++;
switch(a[ai])
{
case 0:
switch(b[bi])
{
case 1:bp++;break;
case 2:ap++;break;
case 3:ap++;break;
case 4:bp++;break;
}
break;
case 1:
switch(b[bi])
{
case 0:ap++;break;
case 2:bp++;break;
case 3:ap++;break;
case 4:bp++;break;
}
break;
case 2:
switch(b[bi])
{
case 0:bp++;break;
case 1:ap++;break;
case 3:bp++;break;
case 4:ap++;break;
}
break;
case 3:
switch(b[bi])
{
case 0:bp++;break;
case 1:bp++;break;
case 2:ap++;break;
case 4:ap++;break;
}
break;
case 4:
switch(b[bi])
{
case 0:ap++;break;
case 1:ap++;break;
case 2:bp++;break;
case 3:bp++;break;
}
break;
}
if(ai==A)
ai=0;
if(bi==B)
bi=0;
}
cout<<ap<<" "<<bp;
return 0;
}
```
by 小猪之最 @ 2017-09-14 22:06:23