@[hmy521](/user/46857) 求所有情况的分值/情况数。
by Smile_Cindy @ 2020-04-09 14:49:24
每一种情况的分值为所有极长连续1的长度三次方和
by Smile_Cindy @ 2020-04-09 14:49:53
@[Alpha](/user/87058) 那样例为啥要除以8
by hmy521 @ 2020-04-09 14:56:30
@[hmy521](/user/46857) 或者我这么跟你解释，每种情况的分值*每种情况的概率。
by Smile_Cindy @ 2020-04-09 14:57:18
@[hmy521](/user/46857) 样例中每种情况的概率都是1/8
by Smile_Cindy @ 2020-04-09 14:57:33
@[Alpha](/user/87058) ok懂了谢谢
by hmy521 @ 2020-04-09 14:58:30