```cpp
#include<iostream>
using namespace std;
int main()
{
long long a[10000];
int b,e,d,n,i;
cin>>n;
for(i=0;n>i;i++)
{
cin>>a[i];
if(a[i]%2==0) cout<<"even"<<endl;
if(a[i]%2!=0) cout<<"odd"<<endl;
}
return 0;
}
```
by s5_gan @ 2017-09-21 16:22:41
**要高精干什么。。。**
判断一个数的奇偶性不是只要看最后一位不就好了吗，用字符串读入
by wycissilly @ 2017-09-21 17:40:59
橙名通过15道？？？？？
by wubaiting2020 @ 2017-10-06 12:44:48
@kkksc03，我觉得应该把这道题数字的大小范围写一下，不然我们就会错
by wubaiting2020 @ 2017-10-06 12:46:13
@[kkksc03](/space/show?uid=1) ，我觉得应该把数据范围放在比较显眼的地方，好多人第一次提交都是因为没有看到数据范围，导致要在提交一遍，连我都是两遍才过而且是过完后才发现有数据范围，所以我认为应该把数据范围放在比较显眼的地方
by 飞翔的金鱼 @ 2017-10-15 20:15:27
# 并不需要高精度
只要用个字符串数组然后读最后一位即可
by Zenurik @ 2017-11-03 11:38:59
// luogu-judger-enable-o2
var
odd:set of char;
n,i:longint;
s:string;
begin
readln(n);
odd:=['1','3','5','7','9'];
for i:=1 to n do
begin
readln(s);
if s[length(s)] in odd then writeln('odd') else writeln('even');
end;
end.
by ttbr5145 @ 2018-02-21 19:21:44
```pascal
// luogu-judger-enable-o2
var
odd:set of char;
n,i:longint;
s:string;
begin
readln(n);
odd:=['1','3','5','7','9'];
for i:=1 to n do
begin
readln(s);
if s[length(s)] in odd then writeln('odd') else writeln('even');
end;
end.
```
by ttbr5145 @ 2018-02-21 19:22:25
@Mark_Kyle###### ######## #### YES
by ttbr5145 @ 2018-02-21 19:23:00