~~btd,jbl?~~
by WanderingTrader @ 2020-06-06 13:28:00
@[wangyutao](/user/29752) 设两个为$(x_1,y_1)and(x_2,y_2)$,则另两个为$(x_1,y_2)and(x_2,y_1)$?
by WanderingTrader @ 2020-06-06 13:29:43
~~勾股定理~~
by Blunt_Feeling @ 2020-06-06 13:30:22
$$((x_1+x_2)/2+(y_1-y_2)/2,(y_1+y_2)/2+(x_2-x_1)/2)$$
$$((x_1+x_2)/2+(y_2-y_1)/2,(y_1+y_2)/2+(x_1-x_2)/2)$$
by 123456zmy @ 2020-06-06 13:30:46
orz
by Sarcasm @ 2020-06-06 13:34:19