你这个高精不能用快读啊。。。毕竟普通的快读存不下，所以建议直接一点，开O2(
by bovine__kebi @ 2020-06-12 20:26:53
变量名好评(
by 星尘_星辰 @ 2020-06-12 20:27:27
O2也要炸
by Richard21477 @ 2020-06-12 20:27:29
还有，qndjr
by bovine__kebi @ 2020-06-12 20:27:33
~~用int128~~
by lndjy @ 2020-06-12 20:27:40
pow()预处理就过了~~完结散花~~
by Richard21477 @ 2020-06-12 20:31:15
```cpp
#include<bits/stdc++.h>
using namespace std;
struct big{
int l;
int a[100000];
bool operator <= (big kkk) const{
if (l!=kkk.l)
return l<kkk.l;
for (int i=l;i>=1;i--)
if (a[i]!=kkk.a[i])
return a[i]<kkk.a[i];
return true;
}/*
big cut(big x,int first,int end){
big y;
y.l=end-first+1;
for (int i=first;i<=end;i++)
y.a[i]=x.a[i-first+1];
return y;
}*/
big operator - (big kkk){
big sc03;
for (int i=1;i<=l;i++){
sc03.a[i]=a[i]-kkk.a[i];
if (sc03.a[i]<0){
sc03.a[i]+=10;
a[i+1]--;
}
}
for (sc03.l=l;sc03.l>=1;sc03.l--){
if (sc03.a[sc03.l]!=0)
break;
}
return sc03;
}
big right(big x,int gos){
big y;
y.l=x.l+gos;
for (int i=1;i<=gos;i++)
y.a[i]=0;
for (int i=1;i<=x.l;i++)
y.a[gos+i]=x.a[i];
return y;
}
big operator / (big kkk){
big sc03;
big tgz;
sc03.l=l;
tgz.l=l-kkk.l+1;
for (int i=1;i<=l;i++)
sc03.a[i]=a[i];
for (int i=l-kkk.l+1;i>=1;i--){
big gyc=right(kkk,i-1);
tgz.a[i]=0;
while (gyc<=sc03){
sc03=sc03-gyc;
tgz.a[i]++;
}
}
if (tgz.a[tgz.l]==0)
tgz.l--;
while (sc03.a[sc03.l]==0&&sc03.l>=2)
sc03.l--;
return tgz;
}
big operator % (big kkk)const{
big sc03;
big tgz;
sc03.l=l;
//tgz.l=l-kkk.l+1;
for (int i=1;i<=l;i++)
sc03.a[i]=a[i];
//while (kkk<=sc03)
// sc03=sc03-kkk;
/*for (int i=l-kkk.l+1;i>=1;i--){
big gyc=right(kkk,i-1);
//tgz.a[i]=0;
while (gyc<=sc03){
sc03=sc03-gyc;
//tgz.a[i]++;
}
}*/
//if (tgz.a[tgz.l]==0)
// tgz.l--;
//while (sc03.a[sc03.l]==0&&sc03.l>=2)
// sc03.l--;
return sc03;
}
};
int main(){
freopen("divide.in","r",stdin);
freopen("divide.out","w",stdout);
string x,y;
while (cin>>x>>y){
int lx,ly;
lx=x.length();
ly=y.length();
big xx,yy;
xx.l=lx;
yy.l=ly;
for (int i=lx;i>=1;i--)
xx.a[i]=x[lx-i]-'0';
for (int i=ly;i>=1;i--)
yy.a[i]=y[lx-i]-'0';
cout<<"ok1"<<endl;
big an1,an2;
//big ans=xx-yy;
//an1=xx/yy;
an2=xx%yy;
/*for (int i=ans.first.l;i>=1;i--)
cout<<ans.first.a[i];
cout<<" ";
for (int i=ans.second.l;i>=1;i--)
cout<<ans.second.a[i];
cout<<endl;*/
}
fclose(stdin);
fclose(stdout);
return 0;
}
```
顺便请dalao康康juruo的高精除
by Richard21477 @ 2020-06-12 20:32:41