好像走了冤枉路...
试试这个数据:
```
9 9
7 7
10
N N W W W S S S E E
```
答案是$4$,走两个$S$,两个$W$.
您的程序输出了$7$.
顺便请修复一下Markdown(
by devans @ 2020-11-05 20:33:05
```cpp
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
int T,x1,x2,y1,y2,ans=0;
char a[55];
int main(){
cin>>x1>>x2;
cin>>y1>>y2;
cin>>T;
for(int i=0;i<T;i++) cin>>a[i];
if(x1==y1&&x2==y2) cout<<0;
for(int i=0;i<T;i++){
if(x1!=y1&&x2==y2){
if(x1>y1){
if(a[i]=='W'){
x1--; ans++;
}
else ans++;
}
if(x1<y1){
if(a[i]=='E'){
x1++; ans++;
}
else ans++;
}
if(x1==y1) break;
}
else if(x1==y1&&x2!=y2){
if(x2>y2){
if(a[i]=='S'){
x2--; ans++;
}
else ans++;
}
if(x2<y2){
if(a[i]=='N'){
x2++; ans++;
}
else ans++;
}
if(x2==y2) break;
}
else if(x1!=y1&&x2!=y2){
if(x1>y1&&x2>y2){
if(a[i]=='W'){
x1--; ans++;
}
else if(a[i]=='S'){
x2--; ans++;
}
else ans++;
}
else if(x1>y1&&x2<y2){
if(a[i]=='W'){
x1--; ans++;
}
else if(a[i]=='N'){
x2++; ans++;
}
else ans++;
}
else if(x1<y1&&x2>y2){
if(a[i]=='E'){
x1++; ans++;
}
else if(a[i]=='S'){
x2--; ans++;
}
else ans++;
}
else if(x1<y1&&x2<y2){
if(a[i]=='E'){
x1++; ans++;
}
else if(a[i]=='N'){
x2++; ans++;
}
else ans++;
}
else if(x1==y1&&x2==y2) break;
}
}
if(x1==y1&&x2==y2) cout<<ans;
else cout<<-1;
return 0;
}
```
by devans @ 2020-11-05 20:34:27
其实没有必要维护目前的位置
可以直接求需要的距离.
还有其实是选择多个时刻而**不是按顺序等到该移动的时候再移动**.
by devans @ 2020-11-05 20:46:59
您可以试试这个代码(我还没试过)
```cpp
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
int T,x1,x2,y1,y2,ans=0;
char a[55];
int main(){
cin>>x1>>x2;
cin>>y1>>y2;
cin>>T;
for(int i=0;i<T;i++) cin>>a[i];
if(x1==y1&&x2==y2) cout<<0;
for(int i=0;i<T;i++){
if(x1!=y1&&x2==y2){
if(x1>y1){
if(a[i]=='W'){
x1--; ans++;
}
//else ans++;
}
if(x1<y1){
if(a[i]=='E'){
x1++; ans++;
}
//else ans++;
}
if(x1==y1) break;
}
else if(x1==y1&&x2!=y2){
if(x2>y2){
if(a[i]=='S'){
x2--; ans++;
}
//else ans++;
}
if(x2<y2){
if(a[i]=='N'){
x2++; ans++;
}
//else ans++;
}
if(x2==y2) break;
}
else if(x1!=y1&&x2!=y2){
if(x1>y1&&x2>y2){
if(a[i]=='W'){
x1--; ans++;
}
else if(a[i]=='S'){
x2--; ans++;
}
//else ans++;
}
else if(x1>y1&&x2<y2){
if(a[i]=='W'){
x1--; ans++;
}
else if(a[i]=='N'){
x2++; ans++;
}
//else ans++;
}
else if(x1<y1&&x2>y2){
if(a[i]=='E'){
x1++; ans++;
}
else if(a[i]=='S'){
x2--; ans++;
}
//else ans++;
}
else if(x1<y1&&x2<y2){
if(a[i]=='E'){
x1++; ans++;
}
else if(a[i]=='N'){
x2++; ans++;
}
//else ans++;
}
else if(x1==y1&&x2==y2) break;
}
}
if(x1==y1&&x2==y2) cout<<ans; else cout<<-1;
return 0;
}
```
by devans @ 2020-11-05 20:48:51
谢谢大佬
by ink！sans @ 2020-11-06 15:58:30