样例全部都通过了啊
by 415gjy @ 2021-01-03 12:20:06
[测试结果](https://www.luogu.com.cn/record/44566287)
by 415gjy @ 2021-01-03 12:22:22
@[1131郭君勇](/user/365801)
下载数据看看
by liuzimingc @ 2021-01-03 12:45:27
输入：
40 10 5
3 4 2 1 0 3 4 2 1 0
3 4 2 1 0
输出：
0 0
没有问题啊
by 415gjy @ 2021-01-03 13:02:38
然而，可悲的是
你的样例4输出的似乎是2 2
by Twistzz__ @ 2021-01-03 14:19:15
?!
by 415gjy @ 2021-01-03 14:55:10
那么怎么改呢？！
by 415gjy @ 2021-01-03 14:56:02
相信我，第一次打表一般都会遗漏一些情况
by Ernst_Thalmann @ 2021-01-03 21:16:30
```cpp
#include <iostream>
//0 表示剪刀，1 表石头，2 表布，3 表蜥蜴人，4表斯波克
using namespace std;
int main()
{
int n, na, nb, a[210], b[210], suma = 0, sumb = 0;
cin >> n >> na >> nb;
for(int i = 0; i < na; i ++)
{
cin >> a[i];
}
for(int i = 0; i < nb; i ++)
{
cin >> b[i];
}
for(int i = 0; i < n; i ++)
{
int idxa = i % na, idxb = i % nb;
if(a[i % na] == b[i % nb]) continue;
if(a[i % na] == 0)
{
if(b[i % nb] == 1) sumb ++;
if(b[i % nb] == 2) suma ++;
if(b[i % nb] == 3) suma ++;
if(b[i % nb] == 4) sumb ++;
}
if(a[i % na] == 1)
{
if(b[i % nb] == 0) suma ++;
if(b[i % nb] == 2) sumb ++;
if(b[i % nb] == 3) suma ++;
if(b[i % nb] == 4) sumb ++;
}
if(a[i % na] == 2)
{
if(b[i % nb] == 0) sumb ++;
if(b[i % nb] == 1) suma ++;
if(b[i % nb] == 3) sumb ++;
if(b[i % nb] == 4) suma ++;
}
if(a[i % na] == 3)
{
if(b[i % nb] == 0) sumb ++;
if(b[i % nb] == 1) sumb ++;
if(b[i % nb] == 2) suma ++;
if(b[i % nb] == 4) suma ++;
}
if(a[i % na] == 4)
{
if(b[i % nb] == 0) suma ++;
if(b[i % nb] == 1) suma ++;
if(b[i % nb] == 2) sumb ++;
if(b[i % nb] == 3) sumb ++;
}
}
cout << suma << " " << sumb;
}
```
by chenyitian @ 2021-02-15 19:11:37
@[chenyitian](/user/364741) thanks
by 415gjy @ 2022-08-01 16:01:23