#include<bits/stdc++.h>
using namespace std;
char c[100];
int a[1000],b[1000];
int main(){
long long l;
int n;
cin>>a[1]>>c[1]>>a[2]>>c[2]>>a[3];
cin>>b[1]>>c[3]>>b[2]>>c[4]>>b[3];
cin>>n;
a[1]=a[1]*3600;
a[2]=a[2]*60;
b[1]=b[1]*3600;
b[2]=b[2]*60;
l=b[1]+b[2]+b[3]-a[1]-a[2]-a[3];
l=l*n;
cout<<l;
return 0;
}
by Rocket_raccoon_ @ 2018-02-05 11:50:16
@[洛必达法则](/space/show?uid=62849) 没你想得那么难,其实只需要算时间差就行了。
by Rocket_raccoon_ @ 2018-02-05 11:51:24
???
你只输字符?
------------
下标后3600是什么?
by 洛必达法则 @ 2018-02-05 12:02:38
@[杨孙毅](/space/show?uid=39533)
by 洛必达法则 @ 2018-02-05 12:02:51
~~???????????????????~~[](https://www.luogu.org/space/show?uid=39533)
by 洛必达法则 @ 2018-02-05 12:17:40
```
#include<bits/stdc++.h>
using namespace std;
char c[100];
int a[1000],b[1000];
int main(){
long long l;
int n;
cin>>a[1]>>c[1]>>a[2]>>c[2]>>a[3];
cin>>b[1]>>c[3]>>b[2]>>c[4]>>b[3];
cin>>n;
a[1]=a[1]*3600;
a[2]=a[2]*60;
b[1]=b[1]*3600;
b[2]=b[2]*60;
l=b[1]+b[2]+b[3]-a[1]-a[2]-a[3];
l=l*n;
cout<<l;
return 0;
}
```
by Rocket_raccoon_ @ 2018-02-05 13:33:52
@[洛必达法则](/space/show?uid=62849)
by Rocket_raccoon_ @ 2018-02-05 13:33:57