need*1.0
by xuan_gong_dong @ 2021-10-17 15:49:22
@[zhouruidi](/user/568243) 整数除舍小数,加一个*1.0或强制类型转换(double())
by Gondor @ 2021-10-17 15:50:41
哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈哈
by baboon @ 2021-10-17 15:54:14
@[Gondor](/user/346514) **like this?**
```cpp
#include<iostream>
#include<cmath>
using namespace std;
int main(){
long double need,a1,a2,b1,b2,c1,c2,a,b,c,out;
cin>>need;
cin>>a1>>a2;
cin>>b1>>b2;
cin>>c1>>c2;
a=ceil(need*1.0/a1)*a2;
b=ceil(need*1.0/b1)*b2;
c=ceil(need*1.0/c1)*c2;
out=min(min(c,b),a);
cout<<out;return 0;
}
```
测试点14 ta~~又双叒叕~~WA了呐...qwq(还是无输出)
by Windows_Update @ 2021-10-17 16:11:43
@[zhouruidi](/user/568243) 我感觉是对的,但是不知道为啥,抱歉
by Gondor @ 2021-10-17 16:35:19
@[Gondor](/user/346514) 还是十分感谢您的回答,我再看看出了什么问题吧,本地运行是有输出的:
**6.99724e+006**(是cout的问题?)
by Windows_Update @ 2021-10-17 16:46:37
cout<<(int)out;
by zouyq2006 @ 2021-10-17 16:48:56
@[zouyq2006](/user/141434) 全AC了,谢谢!
by Windows_Update @ 2021-10-17 16:51:10