80分,TLE了

P3811 【模板】模意义下的乘法逆元

@[LChen](/user/675837) 我绝对不会骗你主要函数: ```cpp //the code is from chenjh #include<bits/stdc++.h> using namespace std; int inv[3000003]; void getinv(int n,int mod){ inv[1]=1; for(int i=2;i<=n;i++) inv[i]=(long long)(mod-mod/i)*inv[mod%i]%mod; } int main(){ int n,p; scanf("%d%d",&n,&p); getinv(n,p); for(int i=1;i<=n;i++) printf("%d\n",inv[i]); return 0; } ```
by cjh20090318 @ 2022-07-22 09:08:31


@[cjh20090318](/user/577880) ![](//图.tk/e)![](//图.tk/e)
by LChen @ 2022-07-22 09:10:41


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