@[黄H睿R](/space/show?uid=80049) 不熟用Python3
by 越学越掂 @ 2018-07-06 18:15:41
@[黄H睿R](/space/show?uid=80049) 不熟用Python3
by Sheffield @ 2018-07-06 18:16:28
#include<bits/stdc++.h>
char a[10000001], b[10000001];
int c[10000001], d[10000001];
int main() {
int i, j;
int la, lb, l;
scanf("%s%s", a, b);
la = strlen(a);
lb = strlen(b);
l = la > lb ? la : lb;
j = 0;
for(i = la - 1; i >= 0; i--) {
c[j] = a[i] - '0';
j++;
}
j = 0;
for(i = lb - 1; i >= 0; i--) {
d[j] = b[i] - '0';
j++;
}
for(i = 0; i < l; i++) {
c[i] = c[i] + d[i];
if(c[i] >= 10) {
c[i] = c[i] - 10;
if(i < l - 1)
c[i + 1]++;
else
printf("1");
}
}
for(i = l - 1; i >= 0; i--)
printf("%d", c[i]);
printf("\n");
return 0;
}
我是文章
by wenzhang @ 2018-07-06 18:53:43
@[黄H睿R](/space/show?uid=80049) 字符和字符加？应该新开两个$int$数组吧！
by XiaoX @ 2018-07-06 19:22:18
@[XiaoX](/space/show?uid=61309)
我已经转化了，看我的atoi函数
by Hexarhy @ 2018-07-08 15:15:03
@[黄H睿R](/space/show?uid=80049) 好吧，你不觉得字符加字符很难受吗....
by XiaoX @ 2018-07-08 15:37:57