这。。谁看得清啊
by tocek_shiki @ 2018-07-18 16:58:57
欢迎使用markdown
by 斗神·君莫笑 @ 2018-07-18 16:59:21
你插入代码在试一下
by Register @ 2018-07-18 17:13:18
要不然看不懂
by Register @ 2018-07-18 17:13:39
```c
#include<stdio.h>
int main()
{
int r, c, sum, count=0;
scanf("%d%d", &r, &c);
int i, j, num[r][c][2]={0};
for(i=0;i<r;i++){
for(j=0;j<c;j++)
scanf("%d", &num[i][j][0]);
}
sum=num[0][0][0];
int near[4]={0}, max;
i=j=0;
printf("0 0\n");
while(count<=r*c){
if(i-1>=0){
if(!num[i-1][j][1])
near[0]=num[i-1][j][0];
else
near[0]=0;
}
if(i+1<=r-1){
if(!num[i+1][j][1])
near[2]=num[i+1][j][0];
else
near[2]=0;
}
if(j+1<=c-1){
if(!num[i][j+1][1])
near[1]=num[i][j+1][0];
else
near[1]=0;
}
if(j-1>=0){
if(!num[i][j-1][1])
near[3]=num[i][j-1][0];
else
near[3]=0;
}
max=0;
for(int k=1;k<4;k++){
if(near[max]<near[k])
max=k;
}
switch(max){
case 0 : i=i-1;sum+=num[i][j][0];num[i][j][1]=num[i][j][0];break;
case 1 : j=j+1;sum+=num[i][j][0];num[i][j][1]=num[i][j][0];break;
case 2 : i=i+1;sum+=num[i][j][0];num[i][j][1]=num[i][j][0];break;
case 3 : j=j-1;sum+=num[i][j][0];num[i][j][1]=num[i][j][0];break;
}
count=i*4+j+1;
printf("%d %d\n", i, j);
}
printf("%d", sum);
return 0;
}
```
by 药飛煌 @ 2018-07-19 10:26:07
谢谢各位大佬帮忙看一下
by 药飛煌 @ 2018-07-19 10:26:39