@[Senpai](/user/821998)
```c
#include <bits/stdc++.h>
using namespace std;
void in(int &x){
char c=getchar();
while (c<'0' || c>'9') c=getchar();
for (x=0; c>='0' && c<='9'; c=getchar())
x=x*10+c-'0';
}
int main (){
float a,b,c;
scanf ("%f %f %f",&a,&b,&c);
float p=a*0.2+b*0.3+c*0.5;
printf ("%.0f",p);
return 0;
}
```
貌似是可以的
by fwhzqr @ 2022-10-05 21:45:22
貌似快一点
```c
#include <stdlib.h>
#include <stdio.h>
int main()
{
int a,b,c,d;
scanf("%d%d%d",&a,&b,&c);
d=0.2*a+0.3*b+0.5*c;
printf("%d",d);
system ("pause");
return 0;
}
```
by Yanb0 @ 2022-10-05 21:56:44
算了，我还是有待提高
by Yanb0 @ 2022-10-05 21:57:18
```cpp
#include<bits/stdc++.h>
#include <cmath>
using namespace std;
int main()
{
int a,b,c;
cin>>a>>b>>c;
cout<<a*0.2+b*0.3+c*0.5;
return 0 ;
}
```
貌似这样更简单（我是蒟蒻，勿喷勿喷）
by yuwuyanqiu @ 2023-06-08 21:02:15
@[Yanb0](/user/821998)
因为这道题的答案是int类型。
C++ AC Code:
```cpp
#include<bits/stdc++.h>
using namespace std;
int a,b,c;
int main(){
scanf("%d%d%d",&a,&b,&c);
printf("%d",a*20/100+b*30/100+c*50/100);
exit(0);
}
```
代码长度：157B；
用时：30ms;
内存：736.00KB。
by _ant_ant @ 2023-08-03 10:07:41
```
#include<iostream>
using namespace std;
int main()
{
long long a,b,c;
cin>>a>>b>>c;
cout<<a*0.2+b*0.3+c*0.5;
}
```
或许这样就好了【狗头】
by sanmu_kangping @ 2023-08-13 21:20:23