是的所以题解似乎有点问题。这样的状态其实是远远不够用的w
by Xiaojian_xiang @ 2016-10-16 10:40:23
那么数据会不会也有问题？
by zx2003 @ 2016-10-16 10:47:36
@[kkksc03](/space/show?uid=1)
by zx2003 @ 2016-10-16 10:48:17
```cpp
#include <stdio.h>
#define chmin(a,b) if ((a) > (b)) { a = (b); }
const int INF = 1000000;
int H, W;
int shop[1020][1020];
int dp[1020][1020][16];
int bc[] = { 0, 1, 1, 2, 1, 2, 2, 3, 1, 2, 2, 3, 2, 3, 3, 4 };
int main()
{
int i, j, k, k2, cost;
char in[1020];
scanf("%d%d", &H, &W);
for (i = 0; i < H + 3; ++i) {
for (j = 0; j < W + 3; ++j) {
shop[i][j] = 0;
for (k = 0; k < 16; ++k) dp[i][j][k] = INF;
}
}
for (i = 0; i < H; ++i) {
scanf("%s", in);
for (j = 0; j < W; ++j) {
shop[i + 1][j + 1] = (in[j] == '.' ? 0 : (in[j] - '0'));
}
}
dp[1][1][15] = 0;
for (i = 1; i <= H; ++i) {
for (j = 1; j <= W; ++j) {
for (k = 0; k < 16; ++k) {
// move to (i + 1, j)
for (k2 = 0; k2 < 16; ++k2) {
if (
((k & 4) == 0) != ((k2 & 8) == 0)
||!(k & 2)
||(bc[k & 1] + bc[k2 & 6] <= 1)
) continue;
cost = dp[i][j][k];
if (k2 & 1) cost += shop[i + 2][j - 1];
if (k2 & 2) cost += shop[i + 2][j];
if (k2 & 4) cost += shop[i + 1][j + 1];
chmin(dp[i + 1][j][k2], cost);
}
// move to (i, j + 1)
for (k2 = 0; k2 < 16; ++k2) {
if (
((k & 2) == 0) != ((k2 & 1) == 0)
||!(k & 4)
||(bc[k & 8] + bc[k2 & 6] <= 1)
) continue;
cost = dp[i][j][k];
if (k2 & 8) cost += shop[i - 1][j + 2];
if (k2 & 4) cost += shop[i][j + 2];
if (k2 & 2) cost += shop[i + 1][j + 1];
chmin(dp[i][j + 1][k2], cost);
}
}
}
}
printf("%d\n", dp[H][W][15]);
return 0;
}
```
by kkksc03 @ 2016-10-16 10:49:39
请问bc数组是什么意思？
by apt123 @ 2016-10-16 11:05:48
@[apt123](/space/show?uid=14769) bc[i]=i在二进制下中一的个数
by kimi0503 @ 2016-10-16 11:25:37
果断状压六个
by DOFY @ 2016-10-16 21:59:49
比赛的时候我请一个银牌爷看了，他一眼看出六个
by DOFY @ 2016-10-16 22:00:23
这里应该是状压左下、下、右、右上四个吧。
麻烦看下std就是写的这四个啊好不好。。
题解写的什么鬼？！
by TA123 @ 2016-10-17 18:39:09