题解是个好东西
by AK_SLS @ 2022-10-17 17:37:57
题解 你值得拥有
by LIjintong @ 2022-10-17 18:05:40
sum = 0; i = 1;
cout << endl;
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= n - i; j++)//先输出空格，空格在n-i列，000 1，前三个0就是n-i（4-1）列，
{
cout << " ";
}
for (int k = n - i + 1; k <= n; k++)//输出数字，从第n-i+1列开始
{
sum++;
if (sum < 10) cout << "0" << sum;//如果<10，输出0+sum
else cout << sum;//直接输出
}
cout << endl;//记得换行
}
by barte @ 2022-10-17 21:39:15
@[barte](/user/781041) 空格是两个空
by barte @ 2022-10-17 21:40:03
@[barte](/user/781041) 谢谢
by paulyang120 @ 2022-10-18 11:06:42
@[AK_SLS](/user/246036) .....嗯(沉思）
by paulyang120 @ 2022-10-18 11:07:06