TAX?
by Y2hlbnlpa2Fp @ 2023-01-07 20:44:02
@[Y2hlbnlpa2Fp](/user/198266) ?
by YuRuochen @ 2023-01-07 20:45:21
@[YuRuochen](/user/658786) 指你输出的
by Adchory @ 2023-01-07 20:45:35
哦，懂了。。。
但是现在60：
```cpp
#include<bits/stdc++.h>
#define N 1000005
using namespace std;
int n,x[N],y[N],a[N],b[N],mina1[N],mina2[N],minb1[N],minb2[N];
int main(){
scanf("%d",&n);
for(int i=1;i<=n;i++) scanf("%d%d",&x[i],&y[i]);
for(int i=1;i<=n;i++) a[i]=x[i]-y[i],b[i]=x[i]-(i==1?y[n]:y[i-1]);
for(int i=1;i<=n;i++) a[i]+=a[i-1];for(int i=n;i>=1;i--) b[i]+=b[i+1];
mina1[0]=mina2[n+1]=minb1[0]=minb2[n+1]=2e9;
for(int i=1;i<=n;i++) mina1[i]=min(mina1[i-1],a[i]),mina2[i]=min(mina2[i+1],a[i]),minb1[i]=min(minb1[i-1],b[i]),minb2[i]=min(minb2[i+1],b[i]);
for(int i=1;i<=n;i++){
if(mina2[i]-a[i-1]>=0&&a[n]-a[i-1]+mina1[i-1]>=0||minb1[i]-b[i+1]>=0&&b[1]-b[i+1]+minb2[i+1]>=0) printf("TAK\n");
else printf("NIE\n");
}
return 0;
}
```
by YuRuochen @ 2023-01-07 20:46:02
@[__haimo__](/user/676921) 什么？
by YuRuochen @ 2023-01-07 20:47:24
我只是说似乎能骗到分（doge
by Ap0calyptic_ @ 2023-01-07 20:48:03
Who can help me ?
by YuRuochen @ 2023-01-07 20:56:01