```python
n = 0
kw = int(input())
if kw <= 150:
n = 0.4463 * kw
elif 151<=kw<=400:
n=0.4463*150+(kw-150)*0.4663
elif kw>400:
n=0.4463*150+(400-150)*0.4663+(kw-400)*0.5663
print('%.1f' % n)
```
by Cosmos999 @ 2023-01-12 15:36:33
很简单啊```c
#include<stdio.h>
int main() {
int n;
double s;
scanf("%d",&n);
if(n<=150) {
s=n*0.4463;
} else if(n<=400) {
s=150*0.4463+(n-150)*0.4663;
} else {
s=150*0.4463+(400-150)*0.4663+(n-400)*0.5663;
}
printf("%.1lf",s);
return 0;
}
```
by yjz468 @ 2023-02-04 17:20:44