@[JNTM5418](/user/710870) 题里不是说s为实数吗，怎么能用整数类型？
by lucky_loser @ 2023-01-15 20:29:16
分成两块，先输出前一个数，判断有无符号，无return0，有再输出第二个数
by chenxizhe2 @ 2023-01-15 20:31:13
@[1234567qwe](/user/658289) 可是这么做明显复杂了
by lucky_loser @ 2023-01-15 20:32:46
@[1234567qwe](/user/658289) 而且整数类型怎么读入小数点？
by lucky_loser @ 2023-01-15 20:36:45
@[JNTM5418](/user/710870) 本题应该用string最方便，整数类型还是别想了吧
by lucky_loser @ 2023-01-15 20:42:04
@[JNTM5418](/user/710870) ```for(int i = n.size();i>=0;i--){```应该改成```for(int i = n.size()-2;i>=0;i--){```
by yyc_qwq @ 2023-01-15 20:43:42
@[JNTM5418](/user/710870) 或者吧```getline(cin,n);```改成```cin>>n;```并把```for(int i = n.size();i>=0;i--)```改成```for(int i = n.size()-1;i>=0;i--)```
by yyc_qwq @ 2023-01-15 20:46:10
@[JNTM5418](/user/710870) ```if(n[i] == ' ') n[i] = '0';```这个没用删掉
by yyc_qwq @ 2023-01-15 20:47:44
@[JNTM5418](/user/710870) 这样整型就可以了
by yyc_qwq @ 2023-01-15 20:48:44