@ chen_zhe
by jeffstart @ 2023-01-31 14:27:34
@[jeffstart](/user/482998) 显然 $k\le {{n\times (n-1)}\over2}$。
by xzy090626 @ 2023-01-31 14:46:54
可能有重边啊
by jeffstart @ 2023-01-31 15:36:45
orz，应该看看讨论区再交题的，开了个1005我就交了，爆零
by TANGXXX @ 2023-04-19 14:02:04
同意
by Dust_Settled @ 2023-10-05 00:35:52