@[KKKZOZ](/user/60925) 求助大佬
by Mr_xiao @ 2023-02-26 16:24:08
这题最好双指针
by Patron_Saint @ 2023-02-26 16:33:22
楼上正解，算法没对，直接枚举每个区间时间复杂度太高了，建议用双指针来做
by KKKZOZ @ 2023-02-26 16:43:28
我为啥这样都能过？
```cpp
#include<bits/stdc++.h>
#include<cstdio>
#include<cstring>
using namespace std;
int main() {
int n,j;
cin>>n;
for(int i=1;i<=n-1;i++) {
int s=0;
for(j=i;s<n;j++) {
s+=j;
}
if(s==n)
cout<<i<<" "<<j-1<<endl;
}
return 0;
}
```
by Silent_Ltcd_2024 @ 2023-02-26 17:09:19
@[Mr_xiao](/user/871152)
by Silent_Ltcd_2024 @ 2023-02-26 17:09:59
@[CSP_AK_zyz](/user/623291) ```java```速度慢
by da_ke @ 2023-02-26 17:10:10
@[WA_Coding_Duck](/user/766675) 这
by Silent_Ltcd_2024 @ 2023-02-26 17:12:56
好，我再试试
by Mr_xiao @ 2023-02-26 17:45:50
```
#include<iostream>
#include<cmath>
using namespace std;
int n;
int sum;
/*
可以用双指针维护一个区间
如果总和sum小了，那么就让右端向右
否则就让左往左
*/
int main(){
cin>>n;
int l = 0,r = 0;
while (l<=r && r<n){
if (sum<n){
r++;
sum+=r;
}else{
if(sum==n) cout<<l<<' '<<r<<endl;
sum-=l;
l++;
}
}
return 0;
}
```
by Lawliet142857 @ 2023-03-21 20:32:28