这题我只能说暴力也没这么麻烦...
by duanxiaobing @ 2023-06-07 19:41:02
蒟蒻奉上一份代码：
```cpp
#include<ostream>
int n,i=2;
int main(){
scanf("%d",&n);
for(;i*i<=n;i++)
if(n%i==0){
printf("%d",n/i);
return 0;
}
}
```
by duanxiaobing @ 2023-06-07 19:46:19