@[zhangchenxi](/user/875250)
if语句中的“break”只能跳出for这一层循环，并不能跳出最外层的while循环，也就是说，存在一种情况，输出Notabletocatch后还会输出Abletocatch
by CyberRiot @ 2023-06-27 23:18:41
@[zhangchenxi](/user/875250)
```cpp
#include <bits/stdc++.h>
using namespace std;
struct xy{
int x,y;
};
int g,n;
xy a[60];
bool cmp(xy a,xy b){
return a.y<b.y;
}
int main(){
cin>>g;
while(g--){
cin>>n;
for(int i=1;i<=n;i++)
cin>>a[i].x>>a[i].y;
sort(a+1,a+1+n,cmp);
a[0].x=0,a[0].y=0;
bool flag=0;
for(int i=1;i<=n;i++){
if(abs(a[i].x-a[i-1].x)>abs(a[i].y-a[i-1].y)) flag=1;
}
if(flag==0) cout<<"Abletocatch"<<endl;
else cout<<"Notabletocatch"<<endl;
}
return 0;
}
```
这样就能过了
[评测记录](https://www.luogu.com.cn/record/113431527)
by CyberRiot @ 2023-06-27 23:21:17
谢谢
by zhangchenx @ 2023-09-16 18:45:39