样例过了,但全部WA

P5741 【深基7.例10】旗鼓相当的对手 - 加强版

```cpp #include<bits/stdc++.h> using namespace std; struct shen{ string ming; int yu,shu,ying,zong; }; //int n,sum[1010],yu_[1010],shu_[1010],ying_[1010]; int n; //string o[1010]; int main(){ // ios::sync_with_stdio(false); // cin.tie(0);cout.tie(0); cin>>n; // struct shen{ // string ming; // int yu,shu,ying,zong; // bool yu_=false,shu_=false,ying_=false; // }; shen a[1010]; for(int i=1;i<=n;i++){ cin>>a[i].ming>>a[i].yu>>a[i].shu>>a[i].ying; // sum[i]=q.yu+q.shu+q.ying; // yu_[i]=q.yu; // shu_[i]=q.shu; // ying_[i]=q.ying; // o[i]=q.ming; a[i].zong=a[i].yu+a[i].shu+a[i].ying; } // for(int j=1;j<n;j++){ // if(abs(a[j].yu-a[j+1].yu)<=5&&abs(a[j].shu-a[j+1].shu)<=5&&abs(a[j].ying-a[j+1].ying)<=5&&abs(a[j].zong-a[j+1].zong)<=10){ // cout<<a[j].ming<<" "<<a[j+1].ming<<endl; // } // } for(int j=1;j<n;j++){ for(int i=j+1;i<=n;i++){ if(abs(a[j].yu-a[i].yu)<=5&&abs(a[j].shu-a[i].shu)<=5&&abs(a[j].ying-a[i].ying)<=5&&abs(a[j].zong-a[i].zong)<=10){ cout<<a[j].ming<<" "<<a[i].ming<<endl;//continue; } } } return 0; } ``` 这样。。。 (别管注释)
by OI_AK_ME @ 2023-07-07 14:56:19


@[OI_AK_ME](/user/980795) 哇 Thanks♪(・ω・)ノ谢谢
by Nemo_ @ 2023-07-07 16:02:34


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