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P5725 【深基4.习8】求三角形

@[chenqile](/user/953664) 给你改了改,你自己比照吧,你这个差太多了,连换行都没有。 ```cpp #include <cstdio> int main(){ int a; scanf("%d", &a); for (int i = 0; i < a; i++){ for (int j = 0; j < a; j++){ int f = i * a + j + 1; if (f <= 9) printf("0"); printf("%d", f); } putchar(10); } putchar(10); int k = 1; for (int i = 0; i < a; i++){ for (int j = 0; j < a - i - 1; j++){ printf(" "); } for (int j = a - i - 1; j < a; j++){ if (k <= 9) printf("0"); printf("%d", k); k++; } putchar(10); } return 0; } ``` 题解好像讲得不是很精简,你可以瞅瞅我的 ```cpp #include<cstdio> int main() { int n,i,j,k; scanf("%d",&n); for(i=0;i<n;i++,putchar(10)) for(j=1;j<=n;j++) printf("%02d",n*i+j); putchar(10); for(i=0,k=1;i<n;i++,putchar(10)) for(j=1;j<=n;j++) if(j>=n-i)printf("%02d",k++); else printf(" "); return 0; } ```
by Terrible @ 2023-07-27 18:33:02


### 也可以这样 ``` #include<bits/stdc++.h> using namespace std; int main(){ int n; cin>>n; int a[n+5][n+5],b[n+5][n+5],c[n+5][n+5]; int cnt=(n+1)*n/2; for(int i=1;i<=n;i++){ for(int j=n;j>=i;j--){ a[i][j]=cnt; cnt--; } } int sum=1; for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ if(sum<10){ cout<<0; } cout<<sum; sum++; } cout<<endl; } cout<<endl; for(int i=1;i<=n;i++){ for(int j=i;j<=n;j++){ b[i][j]=a[i][j]; } } for(int i=n;i>=1;i--){ for(int j=n;j>=i;j--){ c[i][j]=b[i][j]; } } for(int i=n;i>=1;i--){ int tot=i-1; if(tot!=0){ for(int k=1;k<=tot;k++){ cout<<" "; } } for(int j=i;j<=n;j++){ if(c[i][j]<10){ cout<<0; } cout<<c[i][j]; } cout<<endl; } return 0; } ```
by huangmingyisunny1804 @ 2023-08-03 10:43:10


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by jasonshen_ @ 2023-08-10 10:00:25


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