40分求救

P1089 [NOIP2004 提高组] 津津的储蓄计划

```cpp #include <iostream> using namespace std; int main() { int mon = 0, cun = 0, y[15]; for (int i = 0; i < 12; i++) { cin >> y[i]; if (mon + 300 < y[i]) { cout << "-" << i + 1; return 0; } cun += (mon + 300 - y[i]) / 100 * 100; mon = (mon + 300 - y[i]) % 100; } cout << cun * 1.2 + mon; return 0; } ``` 试试能过不()
by boyuanQYlyc @ 2023-08-15 20:12:22


@[EkSulfur](/user/1054137)
by boyuanQYlyc @ 2023-08-15 20:17:21


@[EPGF](/user/960738) 已搞定,感谢
by EkSulfur @ 2023-08-15 22:11:30


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