WA on #5
by GoodLuckCat @ 2023-09-05 09:57:15
精度问题，这个数列实际上就是斐波那契数列，递推即可。
by amend @ 2023-09-05 10:05:00
```cpp
#include<bits/stdc++.h>
using namespace std;
int main()
{
double n;
cin>>n;
printf("%.2lf", (((((pow(((1+(sqrt(5)))/2),(n)))-(pow(((1-(sqrt(5)))/2),(n))))/(sqrt(5))))));
}
```
by wwqwq @ 2023-09-05 10:05:24
改了一下
by wwqwq @ 2023-09-05 10:05:43
@[Huyuhao0215](/user/916579)
by wwqwq @ 2023-09-05 10:05:53
@[wuweiqi](/user/669919) 谢谢，因为我知道答案是整数，所以就先输出整数部分，再输出“.00”
by GoodLuckCat @ 2023-09-05 12:03:55
@[Huyuhao0215](/user/916579) 把int改成long long也行
by wwqwq @ 2023-09-05 12:05:55
@[wuweiqi](/user/669919) 哦，~~就不试了~~
by GoodLuckCat @ 2023-09-05 12:06:39
@[Huyuhao0215](/user/916579) ~~我已经帮你试完了~~
by wwqwq @ 2023-09-05 12:07:15
@[wuweiqi](/user/669919) 看这个啥都有的记录
<https://www.luogu.com.cn/record/123831403>
by GoodLuckCat @ 2023-09-05 12:11:34