$S_{left}=2*\sum_{i={dep}}^mR_i*h_i$
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$V_{left}=\sum_{i={dep}}^m{R_i}^2*h_i$
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所以：$S_{left}=\sum_{i=1}^m\frac{2*V_i}{R_i} >= \sum_{i={dep}}^m\frac{2*V_i}{R_{dep}}=\frac{2*V_{left}}{R_{dep}}$
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by jtzhang @ 2018-10-01 22:31:48
@[jtzhang](/space/show?uid=59989)
frac 请改为 dfrac
by 岚雪 @ 2018-10-01 22:33:48
$S_{left}=\sum_{i=1}^m\dfrac{2*V_i}{R_i} >= \sum_{i={dep}}^m\dfrac{2*V_i}{R_{dep}}=\dfrac{2*V_{left}}{R_{dep}}$
by 岚雪 @ 2018-10-01 22:34:36
$S_{left}=2*\sum_{i={dep}}^mR_i*h_i$
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$V_{left}=\sum_{i={dep}}^m{R_i}^2*h_i$
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所以：$S_{left}=\sum_{i=1}^m\frac{2*V_i}{R_i} >= \sum_{i={dep}}^m\dfrac{2*V_i}{R_{dep}}=\dfrac{2*V_{left}}{R_{dep}}$、
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by jtzhang @ 2018-10-01 22:35:14
请在外层加上displaystyle
$\displaystyle{V_{left}=\sum_{i={dep}}^m{R_i}^2*h_i}$
by 岚雪 @ 2018-10-01 22:36:58
$\displaystyle{S_{left}=\sum_{i=1}^m\dfrac{2*V_i}{R_i} >= \sum_{i={dep}}^m\dfrac{2*V_i}{R_{dep}}=\dfrac{2*V_{left}}{R_{dep}}}$
by 岚雪 @ 2018-10-01 22:38:00
$\huge{\displaystyle{S_{left}=\sum_{i=1}^m\dfrac{2*V_i}{R_i} >= \sum_{i={dep}}^m\dfrac{2*V_i}{R_{dep}}=\dfrac{2*V_{left}}{R_{dep}}}}$
还可以这样/滑稽
by 岚雪 @ 2018-10-01 22:39:15
神仙讨论、QAQ
by ly0216 @ 2019-01-24 14:31:56
# QwQ
#### 大佬
by 矢信 @ 2019-04-11 14:42:25
@[jtzhang](/space/show?uid=59989) 根据实际评测 这个式子有$30$分
by ⑨baka @ 2019-06-23 14:50:36