其实我有个比较简单的写法
by Martin_CPP @ 2023-10-05 17:21:49
```cpp
std::string
```
by Martin_CPP @ 2023-10-05 17:22:34
无非就两种情况:
1 字母 数字 数字
2 数字 数字
所以...
by Martin_CPP @ 2023-10-05 17:24:30
```cpp
#include<iostream>
#define LOG(x) std::cout << x
int main()
{
int t;
std::cin >> t;
int i = 0;
bool flag = true;
char ch = '';
for (; flag == true; )
{
i++;
int a, b;
std::string s;
std::cin >> s;
if (s[0] >= 'a' && s[0] <= 'z')
{
//分别对应 a,b,c 操作
//储存此次操作的字符
}
else
{
//将 s 转换成数字
//使用上一次的字符
//分别判断 a,b,c 操作
}
if (!(i < t))
{
flag = false;
}
}
std::cin.get();
}
```
by Martin_CPP @ 2023-10-05 17:34:16
同求。90pts #2 WA
by ldf1208 @ 2023-10-26 21:31:04