d第一眼简单，下一眼默默退出
by dingzj2022 @ 2023-10-06 20:31:42
```
#include <bits/stdc++.h>
using namespace std;
int a[5010],b[5010],l[5010];
int main(){
int c,d,e,f,g,h,i=110,j,k=0;
cin>>c>>d>>e>>f;
h=e+f;
for(g=1;g<=c;g++){
cin>>a[g]>>b[g];
if(a[g]>h) l[g]=1;
}
while(d>0){
for(g=1;g<=c;g++){
if(l[g]==0){
if(b[g]<i){
i=b[g];
j=g;
}
}
}
l[j]=1;
if(d>=b[j]){
d=d-b[j];
k++;
}
else break;
i=110;
}
cout<<k;
return 0;
}
```
by xzq4121 @ 2023-10-06 20:44:42
@[xzq4121](/user/1054119) 谢谢，已明白，已关注。
by lintylong @ 2023-10-07 19:04:29