@[Dean_code](/user/959579)
$$
\sum_{i = 1}^n \frac{\mathbf{k^i}}{a_i}
$$
by Argvchs @ 2023-10-14 14:33:46
@[Dean_code](/user/959579) 你快速幂写错了，应改成if (b&1) ans = ans * a % c;
by Caiest_Oier @ 2023-10-14 14:35:39
我想题面应该是
$$
\sum\limits_{i=1}^n\frac{k^i}{a_i}
$$
而不是
$$
\sum\limits_{i=1}^n\frac{k^{2^{i-1}}}{a_i}
$$
by Endline @ 2023-10-14 15:26:36
orz,不是看错了题,没注意到k会变化,hhh,然后快速幂写错了,本来以为会过很长时间才会有人会我,洛谷的dalao们太热心啦!!!谢谢!!!
by xiaobu_dean @ 2023-10-14 15:41:13