```c
#include<stdio.h>
#include<string.h>
int main()
{
int c,d,i,A[7],B[7],x=1,xx=1;
char a[7],b[7];
gets(a);
gets(b);
c=strlen(a);
d=strlen(b);
for(i=0;i<c;i++)
{
A[i]=a[i]-'@';
x=x*A[i];
}
for(i=0;i<d;i++)
{
B[i]=a[i]-'@';
xx=xx*B[i];
}
if(x % 47==xx % 47)
printf("GO");
else printf("STAY");
return 0;
}
```
by Reskyllr @ 2018-10-10 12:38:41
A[i]=a[i]-'@';
B[i]=a[i]-'@';
把@改A试试
by miaojiexi @ 2018-10-10 12:47:00
当我没说
by miaojiexi @ 2018-10-10 12:47:38
应该是边乘边模
by miaojiexi @ 2018-10-10 12:48:16
@[Reskydown](/space/show?uid=135688)
by miaojiexi @ 2018-10-10 12:48:22
不然会爆int
by miaojiexi @ 2018-10-10 12:49:03
第二个循环不应该是
B[i]=b[i]-'@';
吗。。。
by 561025p @ 2018-10-10 13:17:01
@[561025p](/space/show?uid=91296) 我去，发现了；；；；；；
by Reskyllr @ 2018-10-10 13:34:13
@[miaojiexi](/space/show?uid=58697)
这题爆不了。。。数据很小。。。
by 561025p @ 2018-10-10 13:38:47
~~这好像只是一道红色的题……~~
by 7KByte @ 2018-10-10 13:39:29