@[andy605](/user/756608) 题目理解有误
by Pitiless_boy @ 2023-10-30 21:02:06
首位数字乘以 1 加上次位数字乘以 2w4td ……以此类推，用所得的结果 $\bmod 11$，所得的余数即为识别码
by Pitiless_boy @ 2023-10-30 21:03:16
乘以2
by Pitiless_boy @ 2023-10-30 21:03:41
麻烦大佬解释得更详细,谢谢!
by andy605 @ 2023-10-30 21:11:08
@[andy605](/user/756608) 就是以:0-670-82162-4 为例，识别码的方法是 (0 * 1 + 6 * 2 + 7 * 3 + 0 * 4 + 8 * 5 + 2 * 6 + 1 * 7 + 6 * 8 + 2 * 9) % 11
by Pitiless_boy @ 2023-10-30 21:23:14
@[andy605](/user/756608) 还有记得按```回复```按钮at，不然看不到你有没有回复
by Pitiless_boy @ 2023-10-30 21:26:07
@[Pitiless_boy](/user/1011137) 感谢大佬,等会儿我再试一下
by andy605 @ 2023-10-30 21:30:29
@[andy605](/user/756608) 好的
by Pitiless_boy @ 2023-10-30 21:31:31