@[aspirationwin](/user/1171139) 你
```cpp
a= min(min(a, b), c);
c= max(max(a, b), c);
```
这个东西可能会把他原来的数据覆盖，直接赋值就可以了
```cpp
mi = min(min(a,b),c);
ma = max(max(a,b),c);
```
by tuanzi_pal @ 2023-11-21 23:27:49
@[tuanzi_pal](/user/695562) 感谢大佬，已解决
by aspirationwin @ 2023-11-22 10:12:01