```
#include<bits/stdc++.h>
using namespace std;
int n;
int f=0;
bool ss(int s){
if(s<2){
return false;
}
for(int i=2;i<=sqrt(s);i++){
if(s%i==0){
return false;
}
}
return true;
}
int main(){
cin>>n;
for(int i=4;i<=n;i+=2){
f=0;
for(int j=2;j<=n;j++){
if(f==1){
break;
}
int k=i-j;
if(ss(j)&&ss(k)){
cout<<i<<'='<<j<<'+'<<k<<endl;
f=1;
break;
}
}
}
return 0;
}
```
by _zuoqingyuan @ 2023-11-26 13:44:34
直接把k求出来就行
by _zuoqingyuan @ 2023-11-26 13:45:12
$k$ 可以由 $i-j$ 得到，所以不用枚举 $k$
by CheZiHe929 @ 2023-11-26 13:45:18
谢谢大佬！
by Danny_chan @ 2023-11-26 16:08:49
@[zuoqingyuan](/user/731650)
谢谢
by Danny_chan @ 2023-11-26 21:14:57