```
#include <iostream>
#include <cstdio>
using namespace std;
int n,a[10010][10010],x=1,y,cnt=2;
int main()
{
scanf("%d",&n);
y=(n+1)/2;
a[x][y]=1;
int now=n*n;
for(int i=2;i<=now;++i)
{
if(x==1&&y!=n)
{
a[n][y+1]=cnt;
x=n;
y+=1;
cnt++;
}
else if(x!=1&&y==n)
{
a[x-1][1]=cnt;
x-=1;
y=1;
cnt++;
}
else if(x==1&&y==n)
{
a[x+1][y]=cnt;
x+=1;
cnt++;
}
else
{
if(a[x-1][y+1]==0)
{
a[x-1][y+1]=cnt;
x-=1;
y+=1;
cnt++;
}
else
{
a[x+1][y]=cnt;
x+=1;
cnt++;
}
}
}
for(int i=1;i<=n;++i)
{
for(int e=1;e<=n;++e)
printf("%d ",a[i][e]);
printf("\n");
}
return 0;
}
```
我看您代码和他很相似,可以参考下
by Gary__NotFound @ 2023-12-29 22:45:26
感谢
by guanchenhui123 @ 2023-12-30 20:06:33