@[Mr_LiuXinan](/user/1229013)
兵卒是可以到x或y为0的坐标上的所以标记马阻挡的地方那几个判断的 > 都改成 >= 就可以了
by tankewei911 @ 2024-02-19 16:29:09
我用你的代码改了一下就AC了！！
```cpp
#include <iostream>
using namespace std;
long long xb, yb, xh, yh, pos[100][100], book[100][100];
int main()
{
ios::sync_with_stdio(false);
cin.tie(0), cout.tie(0);
cin >> xb >> yb >> xh >> yh;
pos[0][0] = 1;
book[xh][yh] = 1;
if (xh >= 2 && yh >= 1)
book[xh - 2][yh - 1] = 1;
if (xh >= 1 && yh >= 2)
book[xh - 1][yh - 2] = 1;
if (yh >= 1)
book[xh + 2][yh - 1] = 1;
if (yh >= 2)
book[xh + 1][yh - 2] = 1;
if (xh >= 2)
book[xh - 2][yh + 1] = 1;
if (xh >= 1)
book[xh - 1][yh + 2] = 1;
book[xh + 2][yh + 1] = 1;
book[xh + 1][yh + 2] = 1;
for (int i = 1; i <= xb; ++i)
{
if (book[i][0] == 0)
pos[i][0] = pos[i - 1][0];
}
for (int i = 1; i <= yb; ++i)
{
if (book[0][i] == 0)
pos[0][i] = pos[0][i - 1];
}
for (int i = 1; i <= xb; ++i)
{
for (int j = 1; j <= yb; ++j)
{
if (book[i][j] == 0)
pos[i][j] = pos[i - 1][j] + pos[i][j - 1];
}
}
cout << pos[xb][yb];
return 0;
}
```
by tankewei911 @ 2024-02-19 16:30:11
OK
by Mr_LiuXinan @ 2024-02-20 08:36:40
@[tankewei114514sb](/user/952747) ok,感谢
by Mr_LiuXinan @ 2024-02-20 08:37:27