1.scr[i]**[b-1]**=0
2.last[i]/=**(b-2)**
3.sort(last,**last+a**,jdg)
by gotocspandbetter @ 2024-02-19 22:41:44
@[wzy20110830](/user/1113551)
by gotocspandbetter @ 2024-02-19 22:42:06
好好读题
写代码时注意一点
by gotocspandbetter @ 2024-02-19 22:43:08