希望更丰富的展现？使用Markdown
by 庄庄庄庄乜 @ 2018-11-03 16:56:55
```cpp
#include<cstdio>
//#include<cmath>
using namespace std;
long long l,s,N,M,a/*正方形(个数)*/,as/*边长*/,b/*矩形*/,bs/*长*/,bss/*宽*/;
int main(){
scanf("%lld%lld",&N,&M);
l=N;s=M;if(N<M){l=M;s=N;}
for(as=1;as<=s;as++){a=a+(l-as+1)*(s-as+1);}
for(bs=1;bs<=l;bs++){for(bss=1;bss<=s;bss++){
if(bs!=bss){b=b+(l-bs+1)*(s-bss+1);}
}}
printf("%lld %lld",a,b);
return 0;
}
```
by SS003 @ 2019-05-18 08:17:35
@[SS003](/space/show?uid=94621) 暴力大法好!
by SS003 @ 2019-05-18 08:17:56
# 暴力解法
```cpp
#include<cstdio>
using namespace std;
int main()
{
int n,m;
scanf("%d %d",&n,&m);
int zheng=0,chang=0,a;
if(n>m)
a=m;
else
a=n;
for(int i=0;i<a;i++)
zheng+=(n-i)*(m-i);
for(int i=1;i<=n;i++)
{
for(int j=1;j<=m;j++)
chang+=(n-i+1)*(m-j+1);
}
chang-=zheng;
printf("%d %d",zheng,chang);
}
```
by 爱嘤撕毯 @ 2020-02-23 13:17:33