AC 求关
```cpp
#include<stdio.h>
#include<string.h>
char ar[10010]={0};
int main()
{
scanf("%s",ar);
int la=strlen(ar);
int a,b,c;
a=0;
b=0;
c=0;
for(int i=0;i<la/5;i++)
{
char x,y;
x=ar[i*5];
y=ar[i*5+3];
if(x=='a')
{
if(y=='b')
a=b;
else if(y=='c')
a=c;
else if(y>='0'&&y<='9')
a=y-48;
}
if(x=='b')
{
if(y=='a')
b=a;
else if(y=='c')
b=c;
else if(y>='0'&&y<='9')
b=y-48;
}
if(x=='c')
{
if(y=='a')
c=a;
else if(y=='b')
c=b;
else if(y>='0'&&y<='9')
c=y-48;
}
}
printf("%d %d %d",a,b,c);
return 0;
}
by HEROBRINEH @ 2024-04-09 18:00:49
第一种：
```cpp
#include<bits/stdc++.h>
using namespace std;
int a=0,b=0,c=0;
void f(int &n,char ch){//注意这里：c已经赋过值了
switch(ch) {
case 'a':
n=a;
break;
case 'b':
n=b;
break;
case 'c':
n=c;
break;
default:
n=ch-'0';
}
}
int main(){
string s;
cin>>s;
for(int i=0;i<s.size();i++){
switch(s[i]) {
case 'a':
f(a,s[i+3]);
break;
case 'b':
f(b,s[i+3]);
break;
case 'c':
f(c,s[i+3]);
break;
}
i+=4;
}
printf("%d %d %d",a,b,c);
return 0;
}
```
by W_Galaxy @ 2024-04-09 18:46:53
第二种也是一样的改法
by W_Galaxy @ 2024-04-09 18:50:56
@[W_Galaxy](/user/1181026) 谢谢
by Lorentz @ 2024-04-21 17:13:47
@[HEROBRINEH](/user/1113507) 谢谢 但是我要是想要答案不如直接抄题解
by Lorentz @ 2024-04-25 17:07:09